How many liters of seawater would have to be processed to recover 1 kilogram of gold?

Let’s learn how many liters of seawater would have to be processed to recover 1 kilogram of gold. The most accurate or helpful solution is served by Yahoo! Answers.

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How many liters of seawater would have to be processed to recover 1 kilogram of gold?

A cubic meter of seawater contains 6 x 10^-6 grams gold. A cubic meter is equal to 1,000 liters. 1000 grams (g) = 1 kilogram (kg) Do you think this recovery operation is feasible?

Answer:

6 x 10^-6 grams = 6 x 10^-9 kilograms We set up an equation to find the amount of water that must be...

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How many liters of seawater would have to be processed to recover 1 kilogram of gold?

A cubic meter of seawater contains 6 x 10^-6 grams gold. A cubic meter is equal to 1,000 liters. 1000 grams (g) = 1 kilogram (kg) Do you think this recovery operation is feasible?

Answer:

1 liter of seawater = 6 x 10^-6 grams of Gold And, 1 kg = 1000g So, 1000 g of gold X 1 Liter of seawater...

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UQKSELJWPXBVZGIPENC6ST3IVA at Yahoo! Answers Mark as irrelevant Undo

How many liters of seawater would have to be processed to recover 1 kilogram of gold?

A cubic meter of seawater contains 6 x 10^-6 grams gold. A cubic meter is equal to 1,000 liters. 1000 grams (g) = 1 kilogram (kg) Do you think this recovery operation is feasible?

Answer:

the calculation of the seawater volume is quite straightforward. It's 1000/ (6 x 10^-6) = 0.167 x 1...

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How many liters of seawater must be processed to obtain 1.4 million kg of bromine?

How many liters of seawater (density 1.025 g/cm^3) must be processed to obtain 1.4 million kg of bromine? Assume the Br- ion concentration is equal to 0.065 g/kg and a recovery rate of 20%. I dont understand how to deal with the recovery rate of 20%...

Answer:

First get your rate with recovery of 100%. There are 0.065 grams recoverable Bromine ions per kilogram...

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Gold is found in seawater at very low levels, about 0.05 by mass.?

Gold is found in seawater at very low levels, about 0.05 ppb by mass. Assuming that gold is worth about $850 per troy ounce, how many liters of seawater would you have to process to obtain $1000000 worth of gold? Assume the density of seawater is 1....

Answer:

how many oz of gold do you need $1000000 / $850/oz = 1176.5 oz how much water contains that much gold...

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Answer:

Wikipedia explains this is great detail. Too much to repeat here.

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TAZ OMEGA '66 at Yahoo! Answers Mark as irrelevant Undo

Iron, lead, copper, and gold are all examples of __________ that are commonly found and processed in the United States and Canada.?

Iron, lead, copper, and gold are all examples of __________ that are commonly found and processed in the United States and Canada. A. fossil fuels B. agricultural products C. ...show more

Answer:

minerals

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How do you recover fine gold particles in an environmentally friendly manner?

In alluvial gold mining very fine gold particles are easily lost in the suspension either in wet or dry wash. How is it possible to recovery these microscopic particles from the suspension in an environmentally way?

Answer:

I'm thinking that it's possible but it also has to be economically feasible. Gold has two properties...

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Westland... at Yahoo! Answers Mark as irrelevant Undo

Answer:

I think it between $1500 to $1800 per oz, so that would be 52,920 to 63,504, but I have ask, how the...

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