PH at the equivalence point?

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How can I find the Ka of an unknown acid if the pH at the equivalence point is given?

I've been trying to figure this problem out for about 3 days now and I still can't get the right answer. My teacher gave us the answer when she saw we were having trouble with it. The answer is 1.6×10^-4 but every signal time I get a different answer. So the problem states a 2.06g solid sample of an unknown monoprotic acid was dissolved in distilled water to produce a 35.0mL solution at 25°C. This solution was then titrated with 0.300M NaOH. The equivalence point was reached when 48.73mL of 0.3...

Answer:

I'm not going to go into specifics (because I struggle with Chemistry myself and all those numbers are...

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Other solutions

Answer:

HNO2 and KOH react in a 1:1 mole ratio: HNO2 + KOH ==> H2O + KNO2 moles HNO2 = M HNO2 x L HNO2 =...

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qtpie555 at Yahoo! Answers Mark as irrelevant Undo

How do I find Ka from pH at equivalence point?

In my chem lab, I titrated an unknown acid with NaOH; the pH at equivalence point is around 7.8 and this occurs at 24.4 mL of NaOH added. The concentration of NaOH is 0.10002 M. the total amount of acid titrated is 25 mL. How would i find the pKa of...

Answer:

Based on your titration data, the concentration of acid is about 0.10 M (you may be able to add another...

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Answer:

Kb = 1.1 x 10^-8 moles HONH2 = 0.020 L x 0.50 M=0.010 moles HCl required to reach the equivalence point...

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Calculating pH at the equivalence point?

Hi, Can anyone tell me if my answers are correct? here's the problem: Calculate the pH at the equivalence point for the titration of 20,00mL of benzoic acide by NaOH of 0,0157M knowing that it takes 23,63mL for neutralization. The pKa of benzoic acide...

Answer:

moles NaOH = 0.0157 x 0.02363 = 0.000371 = moles benzoic acid C6H5COOH + OH- >> C6H5COO- + H2O...

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marie9 at Yahoo! Answers Mark as irrelevant Undo

Calculate the pH at equivalence point?

Ok, I am doing a lab where we are doing a titration of ASA (aspirin) with NaOH. I calculate the moles of ASA to be .0030. We used 31.12ml of NaOH to do the titration. It was a 40l solution of ASA that was .098M. We are supposed to "calculate the...

Answer:

aspirin = HC9H7O4 what is the mass of the aspirin used? what is the molarity of the NaOH? what is the...

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Titration of 35.00 mL of 0.175 M caffeine using a .275 M HCl solution. Calculate pH and equivalence point.?

Calculate pH when 0, 5, 10.5, 17, 21, 26 and 31 mL of HCl are added. What is the equivalence point and it's pH?

Answer:

Haha I wish I knew the answer to this. Dr. O im guessing

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3QF523CPIGYXSASVJGXS3G4XGM at Yahoo! Answers Mark as irrelevant Undo

Find the pH and volume (mL) of 0.0372 M NaOH needed to reach the equivalence point(s) in titrations of the fol

15.8 mL of 0.0868 M H2SO3 (two equivalence points) I already know that the first volume is 36.9 mL and the first pH is 7.13, however I can't figure out the second volume and pH. Thanks,

Answer:

0.0158 Litres @ 0.0868 Molar = 0.001371 moles acid @ 2 H+ ions / moole = 0.002743 moles H+ ion ----...

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David P at Yahoo! Answers Mark as irrelevant Undo

Answer:

At the equivalence point, you have a solution of BH+ in water. This acts as a weak acid by the reaction...

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mastergamer615 at Yahoo! Answers Mark as irrelevant Undo

Answer:

well we need to look at two specific equations on is the reaction of the acid and the base HNO2+NaOH...

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